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5n+3n^2=375
We move all terms to the left:
5n+3n^2-(375)=0
a = 3; b = 5; c = -375;
Δ = b2-4ac
Δ = 52-4·3·(-375)
Δ = 4525
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4525}=\sqrt{25*181}=\sqrt{25}*\sqrt{181}=5\sqrt{181}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{181}}{2*3}=\frac{-5-5\sqrt{181}}{6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{181}}{2*3}=\frac{-5+5\sqrt{181}}{6} $
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